Swift Set intersection()

var A: Set = [2, 3, 5]
var B: Set = [1, 3, 5]

// compute intersection between A and B
print("A n B = ", A.intersection(B))

// Output: A n B =  [5, 3]

intersection() Syntax

The syntax of the set intersection() method is:

set.intersection(otherSet)

Here, set is an object of the Set class.

intersection() Parameters

The intersection() method takes a single parameter:

• otherSet - The set of elements.

Note: The other must be a finite set.

intersection() Return Value

• The intersection() method returns a new set with common elements of set and other (set passed as an argument).

Example 1: Swift Set intersection()

var A: Set = ["a", "c", "d"]
var B: Set = ["c", "b", "e" ]
var C: Set = ["b", "c", "d"]

// compute intersection between A and B 
print("A n B =", A.intersection(B))

// compute intersection between B and C 
print("B n C =", B.intersection(C))

Output

A n B = ["c"]
B n C = ["b", "c"]

Here, we have used the intersection() method to compute the intersection between A and B & B and C respectively.

Example 2: Use of Swift intersection() and Ranges

// create a set that ranges from 1 to 4
var total = Set(1...10)

// compute intersection   
print(total.intersection([5,10,15]))

Output

[10, 5]

Here, 1...10 represents a set of numbers that ranges from 1 to 10 and is assigned to total.

Finally, we have computed the intersection between total and [5,10,15].

Since 5 and 10 are only common, the intersection() method just prints 5 and 10.